log[5](2x+-4)=2

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Solution for log[5](2x+-4)=2 equation:


Simplifying
log[5](2x + -4) = 2

Reorder the terms:
glo * 5(-4 + 2x) = 2

Reorder the terms for easier multiplication:
5glo(-4 + 2x) = 2
(-4 * 5glo + 2x * 5glo) = 2
(-20glo + 10glox) = 2

Solving
-20glo + 10glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -20glo + 10glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -20glo + 10glox = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-1 + -10glo + 5glox) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-1 + -10glo + 5glox)' equal to zero and attempt to solve: Simplifying -1 + -10glo + 5glox = 0 Solving -1 + -10glo + 5glox = 0 Move all terms containing g to the left, all other terms to the right. Add '1' to each side of the equation. -1 + -10glo + 1 + 5glox = 0 + 1 Reorder the terms: -1 + 1 + -10glo + 5glox = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -10glo + 5glox = 0 + 1 -10glo + 5glox = 0 + 1 Combine like terms: 0 + 1 = 1 -10glo + 5glox = 1 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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